5-2[-3-2(4-6)]?

Question

Having trouble figuring the order of operations. Do brackets act as multiplication signs like parentheses do? I have the answer, but cannot, for the life of me, figure out the steps.

Answer 1

PEMDAS... Parenthesis | Exponents | Multiplication | Division | Addition | Subtraction

5-2[-3-2(4-6)]
5-2[-3-2(-2)]
5-2[-3+4]
5-2[1]
5-2= 3

Answer 2

3

Answer 3

Always work brackets from inside out....(4-6)=-2; X-2=+4;
+4-3=+1
+1 X-2=-2
-2+5=+3 (ans)

Answer 4

Brackets don't act as multiplication signs, you just do what is in them first and then put that number into the rest of the equation - if i remember correctly.

5 - 2 [ -3 - 2(4-6)] = -4

5-2 [-3-2(-2)] =
5-2 [-3- -4] =
subracting a negative is adding again
5 -2 [-7] =
5 -2 -7 =
3 -7 =
-4

Answer 5

Always do operands in the parathense first.

5-2 [ -3-2 (4-6) ] = 5-2 [ -3-2 (-2)] = 5-2 [ -3 +4] = 5-2 [ +1] = 5 -2 = 3

Answer 6

5-2[-3-2(4-6)]
= 5-2[-3-2(-2)]
= 5-2[-3+4]
=5-2[1]
=5-2
= 3

Answer 7

first work the aprenthesis

-3 minus 2 is -1
then 4-6 is negitive 2
always when in parenthises x when there are no signs
so -2 x -1 when ever you times two numbers that are negitive you get your answer and then make it positive
so -2x-1=2
3x2=6 and your answer is 6

Answer 8

BEDMAS - in that order
Brackets (including ones within brackets), exponents, division and multiplication, addition and subtraction
answer is 3

Answer 9

Do it in this order: BEDMAS: Brackets, Exponents, Division, Multiplicaton, Addition, and Subtraction.

Answer 10

5-2[-3-2(4-6)]
=5-2[-3-2(-2)]
=5-2[-3+4]
=5-2(1)
=5-2
=3