algebra word problem-enclosing a pool?

Question

rectangular swimming pool is 15 ft by 50 ft has a 6 ft wide sidewalk around it. how much fencing would be needed to enclose the sidewalk? and what is the area of the sidewalk?

what other formuals would i need beside a=lwh? thanks for the help.

typo. a=lw no lwh

Answer 1

Here r the 2 two formulas that you will need for this problem.

a=LW
P=2(L+W)

Find the perimeter of fencing needed.
step 1. We know that the Dimensions of the pool is 15ft by 50ft. And we Know that the side walk is 6ft. Let find the total length and with of the side walks and pool. because there is side walk on all ends of the pool we will need to add 15ft+6ft+6ft=27ft and 50ft+6ft+6ft=62ft

P=2(l+w)
P=2(27ft+62ft)
p=2(89ft)
p= 178ft

so you need 178ft of fencing.

Lets solve for area.

First lets solve for total area.
A=LW
A=62*27
A=1674ft^2

Lets find area of pool.
A=LW
A=15ft*50ft
A=750ft^2

1674^2-750ft^2=a of side walk
924=Area of dside walk.

Answer 2

Adding 6 feet to each side adds 12 to the length and
width each. So the fence encloses 27X62. The
perimeter (or fencing) is 2X(27+62)=178 feet.
The area of the sidewalk is the enclosed area minus
the pool area. That is
27X62-15X50=924 sq. ft.

Answer 3

Add 12 feet (6 feet x 2 sides) to each dimension to determine the dimensions of the pool plus the sidewalk.
Perimeter = L * 2 + W * 2.

Determine the total area and then subtract the area of the pool to determine the area of the sidewalk.

Answer 4

Find the demensions of the pool with the sidewalk [(6 + 15 + 6) + (6 + 50 + 6)] x 2 will give you the perimeter (i.e. the lenght of fence. multiply (6 + 15 + 6) + (6 + 50 + 6) to get the area.

Answer 5

Length of the side walk = 50 +6 +6=62 feet
width of the side walk = 15 +6 +6=27 feet
Perimeter=2(length + width)
Fencing required along side walk = 2(62+27)=178 feet
Area =(Length)x(width)
Area of Side walk= Outer areaincluding side walk and pool
- Area of pool
Area of side walk = (62x27) - (50x15)
=1674 - 750
= 924 sq feet

Answer 6

15' x 50' w/ 6' wide sidewalk...
27' x 62'

27' + 27' + 62' + 62' = 178' perimeter (of fencing)

15' x 50' = 750 sq ft original (pool)
27' x 62' = 1674 sq ft w/ sidewalk

1674 sq ft - 750 sq ft = 924 sq ft is the area of the sidewalk...

Answer 7

I think your question is misstated. You actually asked to enclose the SIDEWALK...which would be perimeter of pool plus outside perimeter of sidewalk. The answers you got pertained to your probable real question, ie to build a fence around the perimeter of the pool/sidewalk complex...unless the test is being tricky, in which case use above to enclose only the sidewalk.

Answer 8

a= lwh ????? what is that?

a = surface (or area)... it's a multiplication of TWO distances, not 3 !!! When you multiply 3 distances together, what you get is volume, not area.

and yes, it's the only formula you need. But you also need to use your brain a bit to find a simple way of computing the value of area and length of fence needed (by combining 2 areas or 2 length of fence in a smart way)