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2 answers

If it is a hollow cylihder, the surface area is doubled also.

2006-09-04 02:11:13 · answer #1 · answered by cherox 3 · 0 0

The surface area of the 'cylinderical' part doubles. But the areas of the ends stay constant. The total area is the sum of those.

For a cylinder of radius r and length l, the area of each end is simply Ae = πr²

The area lf the cylindrical side is
As = 2πrl

So the total surface area is
A = Ae + Ae + As = πr² + πr² + 2πrl = 2πr² + 2πrl
which is frequently factored and written as
A = 2πr(r+l)

Hope that helps.


Doug

2006-09-04 09:16:36 · answer #2 · answered by doug_donaghue 7 · 0 0

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