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explain this pattern CLEARLY and provide the next one in the sequence...

1
11
211
12211
11222211

2006-09-04 00:54:49 · 6 answers · asked by sheldyshawiwongka 2 in Science & Mathematics Mathematics

6 answers

if this is what I think it is the pattern shouldn't be like that...
it should be like this

1
11
21
1211
111221

I'm actually having a problem in translating my answer in English so bear with my temporary glitch in grammar...


first line shows "one"
the second line, based on all other lines, would read as one "one"

meaning that there is one "1"

the next line reads two "1"

meaning there are 2 ones in the previous line.

the next line would read one "2" one "1"

meaning there is one "2" and one "1"

and so on...

the next line would be

312211

2006-09-04 00:58:56 · answer #1 · answered by Hi-kun 2 · 0 0

OK I should tell you, your pattern might be incorrect. A similar pattern I know goes like this:
1
11
21
1211
111221
312211
13112221

which is:
1 (read: there is one one = 11)
11 (read: there is two one = 21)
21 (read: there is one two one one = 1211)
etc...

And finding the pattern on OEIS doesn't yield result too: http://www.research.att.com/~njas/sequences/?q=1+11+211+12211+11222211&language=english&go=Search

2006-09-04 02:12:15 · answer #2 · answered by Lie Ryan 6 · 0 0

The next number in sequence should be

11221222211

2006-09-04 01:40:49 · answer #3 · answered by cooldude 3 · 0 0

one thank you to think of roughly this difficulty is to think of roughly operations that often provide you 0. as an occasion, 0 cases any quantity is 0. So in case you need to use a subset of numbers to get 0 (6-4-2), as an occasion, then basically save multiplying this (0) with the help of all the different numbers. better of success, Catherine

2016-12-18 04:37:16 · answer #4 · answered by kennie 4 · 0 0

213221

2006-09-04 01:15:31 · answer #5 · answered by bob h 3 · 0 0

112221121111

2006-09-04 03:48:22 · answer #6 · answered by Nirmal87 2 · 0 0

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