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If E is Energy, M is Mass and C is the speed of light, solve E=mc2 where the mass equals 1 gram.

2006-09-03 16:19:20 · 9 answers · asked by marklin1972 2 in Science & Mathematics Physics

9 answers

E=C^2M
E=C^2
C=299 792 458 m/s
E=299792458(299792458)
E=8.98755178737e+16 joules
From: nationmaster.com/encyclopedia/E=mc2
A gram of mass completely converts into

* 89,875,517,873,681.764 joules or
* 24,965,421.632 kilowatt-hours or
* 21,480.764 megatons of TNT

But this conversion only occurs with complete conversion. This is not what happens in a nuclear bomb or in a nuclear reactor. The formula is explaining the relationship between mass and energy, not present day nuclear applications. It is describing TOTAL conversion, not the energy released when the nuclear bonds in the nucleus of the atoms are broken, which is what is happening in today's nuclear processes.

;-D total conversion would be a REALLY BIG BANG!

2006-09-03 16:43:50 · answer #1 · answered by China Jon 6 · 0 0

You really don't provide enough information. In this equation, "m" you use is the relavalistic mass, not the rest mass (which is 1 gram). Assuming your mass is not moving (which is would be moving through space if it is on the Earth), then the equation becomes:

E = 0.001 kg x (299,792,458 m/s)^2 [which is the commonly accepted speed of light] gives you 89,875,517,873,681.8 Joules, which can easily be converted to whatever other unit you want.

2006-09-03 23:40:02 · answer #2 · answered by sitflyskygod 2 · 0 0

E = m * c^2
=
.001 kg * 89,875,517,873.682 km^2/sec^2
=
89,875,517,873,682 joules

or

24,967,418.87 kWh -- if supplied as electricity, enough to power the City of Los Angeles for about 6 1/2 hours!

Youbeenkicked and science freak: your original posts that I'm looking at right now are off by a factor of 10^3 because you substituted g for kg (the question was for 1 gram, or .001 kg).

2006-09-03 23:34:07 · answer #3 · answered by EXPO 3 · 0 0

E=MC^2

m=meters s=seconds g=grams
N=Newton (gm/s^2 or mass x acc.) J= joules (SI unit for energy)

E=(1g)(299,792,458 m/s OR 3.0 x 10^8 m/s)^2

E=(1g)(9.0 x 10^16 same as 90000000000000000 m^2/s^2)

E=9.0 x 10^16 gm^2/s^2 >>> 9.0 x 10^16 N-m >>> 9.0 x 10^16 J

2006-09-03 23:36:16 · answer #4 · answered by Youbeenkickedoutofamarinebase? 1 · 0 0

E = 1 x speed of light x 2

excuse my brain fart

E = 1 x (speed of light)^2

2006-09-03 23:25:10 · answer #5 · answered by DexterLoxley 3 · 0 0

If you give the energy in joules, the mass must be in kg. A joule is one kg*m/sec^2

2006-09-03 23:59:38 · answer #6 · answered by gp4rts 7 · 0 0

That means you have 1 gram of dope

2006-09-04 01:20:35 · answer #7 · answered by Anonymous · 0 1

if you have one gram of anything worth using that equation on, stay the heck away from me.

2006-09-03 23:28:02 · answer #8 · answered by abcdefghijk 4 · 0 0

uh,... do you mean an 8 ball is woth 1 gram?

2006-09-03 23:24:45 · answer #9 · answered by peregrine003 2 · 0 1

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