English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

okay, so i got these math problems in class and i cant get the answers. the problems are: ABC + DEF = GHI and ADG + BDH = CFI. letters A through I have to be the numbers 1 through 9, and the numbers have to work for both problems, like if A = 3 in the first problem, A had to equal 3 in the second problem. if you get it , i LOVE YOU SO MUCH!!

2006-09-03 15:09:44 · 6 answers · asked by ? 2 in Education & Reference Trivia

its not really homework. the teacher asked if any of us could figure it out, since were his highest math class(only geometry, though). his nephew sent it to him because he couldnt figure it out, and my teacher couldnt figure it out, so he asked the class to. so technically, im not cheating ^_^ and ive tried a whole load of number combinations. seriously--nearly 150, at least, by now.

2006-09-03 15:22:53 · update #1

it would be 1+2+3

2006-09-03 15:28:08 · update #2

NOOO i meant 123

2006-09-03 15:28:27 · update #3

i had it right the first time...
ABC + DEF = GHI and ADG = BEH = CFI

2006-09-03 15:59:06 · update #4

gahh, my mistake, im sorry!

2006-09-03 15:59:33 · update #5

once again, another typo. abc + def = ghi and adg + beh = cfi

2006-09-03 16:01:59 · update #6

6 answers

I can't figure it out yet, but I'll keep trying. Here's some stuff I do know:

Either C + F = I OR C + F - 10 = I
Either G + H = I OR G + H - 10 - I
If G + H = I, F is an even number and D is not equal to five.
A + D < 10
A + B < 10

The most that I've been able to simplify this formulaicly is:

8D + E - 9B = (G + H - C - F) / 10

Sorry. I'll think about it more tommorrow if you don't have an answer by then.

EDIT:
I don't think that there is a solution to this problem. I wrote a C++ program to test every possible number combination. There are tons of combinations that make both formulas true, but none use each digit only once.

I think you can tell your teacher that either the problem is written incorrectly, or someone is screwing with him.

2006-09-03 16:35:29 · answer #1 · answered by marbledog 6 · 2 0

Well it depends on what the sequence means. Assume A=1, B=2, and C=3. Would it literally be "123", or 1x2x3. There's a big difference between 6 and 123.

2006-09-03 15:27:35 · answer #2 · answered by Anonymous · 0 0

Did you perhaps mean ABC+DEF=GHI and ADG+BEH=CFI
or did you type it right the first time?

2006-09-03 15:57:55 · answer #3 · answered by Mommy-of-Twins 4 · 0 0

There may be a quick solve formula but I've never seen it and have a terrible time at this type of question. Note that c + f = i and g + h = i also. b + e + carry over from c + f = h and d + d + carry over from g + h = f. Just keep substituting until you get the answers.

2006-09-03 15:21:07 · answer #4 · answered by St N 7 · 0 1

well, honestly, i think your cheating on your math homework... the only way you'll understand how its done is if you do it and figure it out yourself!

2006-09-03 15:18:57 · answer #5 · answered by Anonymous · 0 1

refer to www.mathfun.com

2006-09-05 20:55:50 · answer #6 · answered by ? 5 · 0 0

fedest.com, questions and answers