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4 answers

epends on the mass and size. sorry need more info
its true, a beach ball that is 50 foot in diamater has so much surface area that it wouldnt travel nearly as far as a golf ball, or how about a football, its more aerodynamic. there are alot of factors

2006-09-03 14:42:38 · answer #1 · answered by Anonymous · 0 1

The easiest way and quickest way to handle this type of problem is to understand that the potential energy at the top is the same as the original kinetic energy at the bottom.

K.E. = 1/2(Mass)Velocity^2 = potential energy =Mass*height*g

notice that mass cancels out since it is the same on both sides

(1./2)(Velocity^2) /(acceleration due to gravity) = height

If the ball was thrown at an angle this equation would not work.

Make certain to include units in your answer, to avoid error.

2006-09-03 22:09:12 · answer #2 · answered by Anonymous · 0 0

Position function:
y = 0 + (15)*t - (1/2)(9.8)*t^2

y' = 15 - 9.8t = velocity
velocity = zero at the highest point.

0 = 15 - 9.8t
t = 15/9.8
=1.53 seconds

Plug t = 1.53 into the position function
y = 0 + (15)*(1.53) - (1/2)(9.8)*(1.53)^2
y = 11.58 meters

2006-09-03 21:43:19 · answer #3 · answered by Anonymous · 0 1

vf^2=Vi^2+2ad
0=15^2+2(9.81)(d)
0=225+19.62(d)
-225=19.62(d)

d~11.49m

2006-09-03 21:45:09 · answer #4 · answered by Rajan 3 · 0 1

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