2006-09-03 14:04:12 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
get a closed box and fill it with water, then dump that water into a measuring cup and see what it gets up to
then put a ball in that same box and fill it with water and close it (level it off)
then dump that water into a measuring container and then subtract the 2nd from the 1st and the difference is approx. the volume of the ball
2006-09-03 14:06:36 · answer #1 · answered by ĵōē¥ → đ 6 · 0⤊ 0⤋
First method: Measure the diameter of the tennis ball (width of the ball at the widest point). Now apply the formula for the volume of a sphere. (Pi/6) d^3 (pi divided by 6, times the diameter to the third power [cubed]). An alternative formula is (4 Pi/3)r^3 or 4 times pi divided by 3, times the radius to the third power [cubed]. The radius is half the diameter.
Second method: Get a water tight container big enough to hold the tennis ball with no trouble that has an open top. Place a pan beneath the container to catch the overflow. Fill a container to the brim with water so that one more drop will cause overflow. Float the tennis ball on the surface. Then take a flat object like a clipboard and press down until the board is resting on the top edge of the container and the tennis ball is totally submerged. Remove the board. Set aside the container and ball. Carefully pour the water from the pan into a graduated cylinder and measure the amount of water displaced.
2006-09-03 14:25:04 · answer #2 · answered by Magic One 6 · 0⤊ 0⤋
Measure the circumference of the ball. Divide that by π to find the diameter, divide by 2 to find the radius, then use the formula for the volume of a sphere: (4/3)πr^3.
Or use the displacement method. How much water does the tennis ball displace. An earlier answer described that method.
2006-09-03 14:11:56 · answer #3 · answered by just♪wondering 7 · 0⤊ 0⤋
well one way is to take a gradualted cylinder(or one large enough to fit a tennis ball) and have it measured with water to a certain number then drop the tennis ball in to the cylinder then subract the orginal measurement to the new one to get the volume or length x width x height
2006-09-03 16:38:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I know the diameter is 2.5 in.
you take 1/6 times phi times 3 to the 3rd power.
Good luck
2006-09-03 14:09:33 · answer #5 · answered by Feather 3 · 0⤊ 0⤋
Easy one...Since it is a compliant sealed sphere, you need to lower the atmospheric pressure around the ball (think "pull a vacuum") to get it through the hole. Release the vacuum to return to normal size. Cool Huh?
2016-03-17 07:30:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋
http://members.shaw.ca/mathrules/amath10/volsphere.htm
bottom of the page
2006-09-03 14:07:20 · answer #7 · answered by Lynx 2 · 0⤊ 0⤋