......Use a metric tape measure, that way you will start getting used to the metric system. Then measure both sides and multiply one by the other, this will give you the square area.
2006-09-03 12:36:24
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answer #1
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answered by KWB 3
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Your floor is 11.08333333 square yards which is 9.2671075 square meters. Get 10 sq meters of laminate to be on the safe side.
2006-09-04 10:05:55
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answer #2
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answered by Gobansoar 2
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Multiply the length of the room by the width. In this case you need just over 9 metres so buy 10
2006-09-07 11:02:38
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answer #3
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answered by wullie l 2
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im english and very good at maths so , yiou get the answer by multiplying the two units of size together , So: 15 X 12.5 = 187.5 Square feet , as 6 inches = 1/2 a foot. happy to help , good lick , : ) (not so good at typing though lol.
2016-03-26 21:04:53
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answer #4
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answered by Anonymous
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It's a little over 9 square meters so you'll need at least 10 in case of any wastage in cutting.
3 meters is 9'10"
2006-09-03 12:32:59
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answer #5
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answered by Anonymous
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3 meters= 10ft take the 6 inches from the 10ft 6ins and add it to
9ft 6ins and you now have 10ft x 10ft or 3mtrs x 3 mtrs.
3 x 3= 9mtrs. you then add an extra meter for every 10 so in
your case you need 11 meters.
2006-09-03 12:50:49
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answer #6
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answered by Anonymous
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By my math, it's about 9.27 m².
Remember to buy more, because typically laminate flooring is laid staggered, and you may run into a defect or two and you might make a mistake or two.…
2006-09-03 12:45:14
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answer #7
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answered by Anonymous
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Use the other side of the tape measure - it has metres on it... If you don't have a tape measure, I suggest you don't attempt the floor.
2006-09-04 01:00:20
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answer #8
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answered by Steel Lady 2
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If you have a calculator handy, (I haven't), divide 126 by 39.37, and divide 114 by 39.37, and multiply the answes together. That's the area in square metres.
2006-09-03 12:28:28
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answer #9
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answered by Hy 7
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A metre is 3ft3", so you`re looking at 4 metres (11ft) x 3 metres (9ft9"), which is 12 square metres.
2006-09-03 12:36:47
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answer #10
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answered by Anonymous
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