Evaluate: lim (2 - x)
........ . . . . . ... x =>2+ |2 - x|
2006-09-03 12:14:09 · 8 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
This looks strange, but I'll try it. Suppose f(x) = 2 - x > 0. This means x < 2.
Then we want lim f(x) as x ==> 2+2-x = 4 - x. Add x to both sides, to get 2x ==> 4, or x ==> 2 (from the left, since x<2).
In this case, the limit of f(x) is zero, and f(x) > 0 for all x as x approaches the limit 2 from the left.
Now suppose f(x) = 2 - x < 0. This means x > 2.
And this time we want lim f(x) as x ==> 2 - 2 + x. Subtract x from both sides to get 0 ==> 0. In this case (for x > 2), I'd say
So for x < 2, your limit is zero as x approaches 2 from the left, and for x > 2, the limit is undefined.
2006-09-03 13:17:57 · answer #1 · answered by bpiguy 7 · 0⤊ 0⤋
isn't the lim (2 - x) = 2 - lim (x) ?
2006-09-03 19:24:25 · answer #2 · answered by Anonymous · 0⤊ 1⤋
it ought to be -|2-x|
by continuously replacing x with 2+|2-x|, we get:
lim = 2 - (2 + |2 - x|)
= -|2 - x|
= -|2-(2+|2-x|)|
= -|-|2-x||
= -|-|2-(2+|2-x|)||
= -|-|-|2-x|||
...ad nauseum, but you can see that all of this, no matter how far you take it, will boil down to -|2-x|
2006-09-03 19:43:48 · answer #3 · answered by Argon 3 · 0⤊ 0⤋
limit as x approaches what?, what is the function?
2006-09-03 19:23:04 · answer #4 · answered by Wocka wocka 6 · 0⤊ 0⤋
x cannot approach a function of itself, jackass. The answer will be complex, not real, but you are a jackass anyway
2006-09-03 19:47:58 · answer #5 · answered by copenhagen smile 4 · 0⤊ 3⤋
ahhhhhh wow you must be really smart if you can answer that one!!
2006-09-03 19:20:39 · answer #6 · answered by gigglywiggly426 2 · 0⤊ 1⤋
wow, that's a hard one I really can't help you with it sorry :(
2006-09-03 19:17:56 · answer #7 · answered by GirlyGirl 1 · 0⤊ 1⤋
the answer is I DON'T KNOW
2006-09-03 19:29:18 · answer #8 · answered by Anonymous · 0⤊ 1⤋