2006-09-03 12:05:48 · 15 answers · asked by Sharon B 1 in Science & Mathematics ➔ Mathematics
It is impossible, because an odd number of odd numbers will always be an odd number. That may sound strange, but think about it. Add up any five odd numbers and the sum will always be odd.
This is a very ODD question.
2006-09-03 12:09:30 · answer #1 · answered by FlashGordon 3 · 3⤊ 1⤋
1+1+1+3+3+5=14
2006-09-03 19:12:01 · answer #2 · answered by Anonymous · 2⤊ 1⤋
1, 1+1+1+1
2006-09-03 19:12:57 · answer #3 · answered by rebekah u 5 · 0⤊ 0⤋
11 1 1 1
2006-09-03 19:07:35 · answer #4 · answered by Cirric 7 · 0⤊ 0⤋
Assume they are all positive. An odd number is of the form 2n+1. So
14 = 2a+1+2b+1+2c+1+2d+1+2e+1.
This means 9 = 2(a+b+c+d+e). Now a, b, c, d, and e are integers, So how can their sum be 9/2? Problem has no solution.
Maybe it has one if you change the definition of "odd". It is true that
14 = 7 + 7 + 1 + (-1/2+sqrt(-3)/2) + (-1/2-sqrt(-3)/2)
and all of these numbers are odd - don't you agree with me that numbers like (-1/2+sqrt(-3)/2) are pretty odd-looking numbers? They look weird to me.
2006-09-04 00:07:05 · answer #5 · answered by alnitaka 4 · 0⤊ 0⤋
-. 5 +1 +1 +13+ -.5=14
2006-09-03 20:12:04 · answer #6 · answered by cab veteran 5 · 0⤊ 0⤋
minus 1 plus 3 plus 5 plus 7
2006-09-03 19:15:09 · answer #7 · answered by neverteatea1953 2 · 0⤊ 0⤋
do they all have to be different numbers or can some be the same? btw, flash is wrong, what about, for instance, 7+3=10? two odd numbers making an even one, that... anyway, does it all have to be same mathematical operations? cos if you only add there is no correct solution to the problem...
2006-09-03 19:18:31 · answer #8 · answered by nerdyhermione 4 · 0⤊ 0⤋
Five odd numbers can't give you an even number. Think about it - if you multiplied two odd numbers you'd still get an odd number: it's the same as summing an odd number of odd numbers.
2006-09-03 19:13:33 · answer #9 · answered by woggish_candy 2 · 1⤊ 1⤋
1-1-1-5-6
2006-09-03 19:13:42 · answer #10 · answered by Anonymous · 1⤊ 0⤋