The equation of the line through 4,1 and is parallel to the line 5x + 5y = 2 can be written y=mx+b where m= ____ and b = _________
2006-09-03 12:01:45 · 4 answers · asked by dudefungame 2 in Education & Reference ➔ Homework Help
I meant perpendicular, not parallel
2006-09-03 12:13:28 · update #1
In your line equation, m is the slope. By saying a line is parallel to another, you are saying that the slopes are the same. The equation of the parallel line can be put into the form y = ax+c by rearranging terms 5y = 2-5x, or y =2/5 - x = -x+2/5; the slope, by comparing with the above, is -1. So m =-1. To get c, enter the coordinates of the given pass-through point into the equation. Those coordinates are x = 4, y =1. You will get 1 = -4 + b, so b = 5.
EDIT: I just saw that you meant perpendicular, not parallel. In that case the slope is the negative of the slope of the perpendicular line, so m = 1. Then for the points (4,1) 1 = 4 + b. b = -3
2006-09-03 12:17:10 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
m=1 and b=-3
2006-09-03 19:20:26 · answer #2 · answered by colombianqt2112 2 · 0⤊ 0⤋
ok...
5x+5y=2
5y=-5x+2
y= -1x + 2/5
perpendicular to that
slope (or m) = 1
y=x+b
1=4+b
b (intercept)=-3
so the final equation is y=x-3
2006-09-03 19:55:45 · answer #3 · answered by musicpetlover 2 · 0⤊ 0⤋
m=slope b= y intercept x= the cornante(4,1)
2006-09-03 19:06:10 · answer #4 · answered by *lol*idk.my.bff.jill*lol* 2 · 0⤊ 0⤋