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square any #, then double the result. Is your answer always sometimes or never greater then the result of doubling the #, then squaring it? justify your answer

2006-09-03 11:10:00 · 11 answers · asked by blue october 3 in Education & Reference Homework Help

11 answers

The first situation is never greater than the second situation for all x except zero.

2006-09-07 17:09:52 · answer #1 · answered by zahbudar 6 · 0 0

Sometimes greater. Is you square 0 and then double it you still get 0. Any other number would be greater because squaring a negative number makes it a positive.

2006-09-03 18:17:20 · answer #2 · answered by mlc24_1980 3 · 0 0

if u were to square the number 2 u get 4 and u also get 4 if u double your number other than that the answer is always greater if u were to square it so i would have to say my answer would be sometimes

2006-09-03 18:50:32 · answer #3 · answered by joshua f 1 · 0 0

Sometimes. Essentially you're dealing with two functions, 2x^2 and (2x)^2, which is the same as 2x^2 and 4x^2. Since the square removes all negatives, the second one is twice as big for all numbers except 0, where it is the same.

2006-09-03 18:14:18 · answer #4 · answered by Anonymous · 0 0

well thats sometimes

if you pick 4 and square it that 16. then double it is 2.

if you pick 4 again and double it thats 8 and double it again is 16.

i'm not really sure whats your question though so i just answered by what i tihnk it is.

2006-09-03 18:14:20 · answer #5 · answered by alexis.=) 4 · 0 0

sometimes. re: fractions

3 squared x2 = 18

1/3 squared x2 = 2/9 (less than 3/9=1/3)

as a rule, it works less if and only if the number you're looking for, x, is greater than -1/2 but lesser than 1/2

youre welcome

2006-09-03 18:18:23 · answer #6 · answered by ianaz116 2 · 0 0

Try 0

2006-09-03 18:15:19 · answer #7 · answered by Anonymous · 1 0

Ha ha! Not only does this punk have the guts to ask others to do her homework, she says 'justify your answer'- like we owe her something!

2006-09-03 18:15:46 · answer #8 · answered by Anonymous · 1 1

the latter is always greater for all integers.
2x^2 is less than (2x)^2.

2006-09-03 18:26:27 · answer #9 · answered by Master M 3 · 0 0

always greater, because thats the answer

2006-09-03 18:15:35 · answer #10 · answered by zrogerz69 4 · 0 1

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