How do i find the zeros of this function?

0 ⤊

How do i find the zeros of this function?

f(x)=e^2x-13e^x+36

2006-09-03 08:03:24 · 3 answers · asked by Th_hT 1 in Science & Mathematics ➔ Mathematics

3 answers

say e^x = y

then your equation is
y^2 - 13y + 36 = 0

(y - 9)(y - 4) = 0

so, y = 9 or y = 4

or e^x = 9 and e^x = 4

x = log 9
similarly x = log 4 is the other solution

2006-09-03 08:05:52 · answer #1 · answered by DG 3 · 0⤊ 0⤋

you solve for x

2006-09-03 08:11:38 · answer #2 · answered by felicia m 1 · 0⤊ 0⤋

Factor out............

2006-09-03 08:07:44 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋