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A 85% (w/w) solution of H3PO4 (98.00 g/mol) has a density of 1.71 g/mL. What is the molarity of this solution?

2006-09-03 07:48:44 · 3 answers · asked by vem1225 1 in Science & Mathematics Chemistry

3 answers

w/w means weight by weight.

1 l of the soln weighs = 1.71x1000 g = 1710 g

Mass of H3PO4 present = 0.85 x 1710 g = 1453.5

Number of moles of H3PO4 = 1453.5/98 = 14.83

Thus molarity is 14.83

2006-09-03 08:00:12 · answer #1 · answered by ag_iitkgp 7 · 1 0

w/w
an abbreviation for "by weight," used in chemistry and pharmacology to describe the concentration of a substance in a mixture or solution. Properly speaking, 85% w/w means that the mass of the substance is85% of the total mass of the solution or mixture. The metric symbol g/g has the same meaning as w/w.

2006-09-03 14:59:53 · answer #2 · answered by sms 2 · 1 0

d=m/V
1,71= m/1000ml ( if we have 1 lt solution)

m=1710g (weight of the solution)

100 g solution contains 85 g H3PO4
1710 g solution contains x g H3PO4
-----------------------------------------------
x=1453 g H3PO4

n=m/Ma

n=1453/98
n=14,82 mol

M=n/V
M=14,82/1

M= 14,82 mol/lt

2006-09-03 15:05:40 · answer #3 · answered by cemilturan 1 · 0 0

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