A student prepares a solution of carbonate-free NaOH. Upon performing a rough titration, the student finds the concentration to be 0.0625 M instead of 0.1000 M. Assuming that the volume of the solution is 950.0 mL, how many grams of sodium hydroxide should be added to the solution to produce a concentration as close as possible the desired 0.1000 M? (Assume that the sodium hydroxide is carbonate-free.)
2006-09-03 07:47:11 · 2 answers · asked by vem1225 1 in Science & Mathematics ➔ Chemistry
Moles to be added = Moles reqd. - moles present
= (0.1-0.0625)*950/1000 = 0.035625 moles
So, gms of NaOH = 40 * 0.03625 gm
= 1.45 gm
2006-09-03 08:00:01 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Find how many grams per mole are in NAOH using molecular formula
Know that molarity = moles/liter
Then plug it into the above equation
2006-09-03 14:56:42 · answer #2 · answered by Yentl 4 · 0⤊ 0⤋