Ionly do the cases that P>1 and Q>1
the number of moves you make to the North are P-1
the number of moves you make to the East are Q-1
the order of the moves doesnt matter You can do first all the North's then the East, or first some Noths then some easts.
So in total you do P+Q-2 moves , imagine a string of P+Q-2 signs, put P-1 plus signs and Q -1minus signs in it, this can be done in (P+Q-2) C (P-1) or which is the same (P+Q-2) C (Q-1)
P =1 then there are Q-1 moves
Q = 1 then there are P-1 moves
2006-09-03 09:19:43
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answer #1
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answered by gjmb1960 7
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If the rook is not allowed to go the a square more than once, then at any point, the rook has 2 options to go to north or east
so, ur answer is 16C8 ways
Not 14C7 as said in the previous answer. That would be so, if the chess grid in 7x7
2006-09-03 07:59:40
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answer #2
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answered by DG 3
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The total possible number of ways is 14C7, or 3432. To get from corner to corner moving one space at a time, you have to take 7 moves north and 7 moves east. You're counting 14 moves (in total), taken 7 (north moves) at a time.
2006-09-03 07:50:46
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answer #3
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answered by Louise 5
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You can only make p-1 moves to the east and q-1 north. as you must make these moves and the order that you take these moves determine your path, you have (p-1)(q-1)
2006-09-10 10:03:04
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answer #4
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answered by firstlennsman 1
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Well, if the rook is allowed to visit the same space twice, it would be infinite.
If not, I have no idea.
2006-09-03 07:43:17
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answer #5
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answered by Anonymous
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It could be any way. Up, down, any direction. It's infinite.
2006-09-08 18:11:37
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answer #6
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answered by _anonymous_ 4
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just take the freeway LOL
2006-09-10 05:27:54
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answer #7
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answered by G♥♥G♥♥ღ 4
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