The midpoint of those two points is (4, 9/2). (9/2 is the same as 4.5)
The slope between those points is 5/2. So the slope of the perpendicular bisector (which is what we want) is (-2/5).
Using point-slope, the equation is
y - 9/2 = (-2/5)(x - 4) = (-2/5)x + 8/5
y = (-2/5)x + (8/5 + 9/2) = (-2/5)x + (16 + 45)/10
y = (-2/5)x + 61/10
Or you can write it as
y = 6.1 - 0.4x
2006-09-03 06:13:55
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answer #1
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answered by bpiguy 7
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That equation can be found by two methods
that is finding the perpendicular line equation through
the mid point of the line segment.
OR
using distance formula
now I use distance formula and find out
(X-3)^2+(Y-2)^2 = (X-5)^2+(Y-7)^2
=> X^2-6X+9+Y^2-4Y+4 = X^2-10X+25 +Y^2-14Y+49
=> -6X-4Y+13+10X+14Y-74=0
=> 4X+10Y-61 =0
THE REQUIRED EQUATION
2006-09-03 06:03:13
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answer #2
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answered by spnchennai 1
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2016-12-18 04:07:10
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answer #3
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answered by ? 4
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-0,4*x+6,1=y . I'm bored . Just give me 10 points , OK ? :)
This is the right one .
2006-09-03 05:57:04
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answer #4
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answered by d13 666 2
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y=-5.5+2.5x
2006-09-03 05:53:22
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answer #5
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answered by Lolla 2
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