sec/sin - sin/cos =? and sec(sec - cos) = ? thnx if you could help me...really need it right now
2006-09-03 01:38:28 · 6 answers · asked by Lorenz 2 in Education & Reference ➔ Homework Help
I mean prove the following identities..
2006-09-03 16:25:45 · update #1
whats the question? over my head sorry
2006-09-03 03:11:34 · answer #1 · answered by blank 5 · 0⤊ 0⤋
sin/cos =tan, sec/sin=1, sec(sec-cos)=0
2006-09-09 16:14:50 · answer #2 · answered by Sankaranarayanan R 2 · 0⤊ 0⤋
well the second one is sec^2 - 1 = tan^2
im still working on #1
2006-09-09 11:43:54 · answer #3 · answered by yahoo answers son of a gun 1 · 0⤊ 0⤋
1=tan2
2006-09-09 04:38:15 · answer #4 · answered by red_star_56 4 · 0⤊ 0⤋
1) sec /sin - sin/cos = (1/sec.cos) - (sin/cos) = (1-sin2)/(sin.cos) = cos2/sin.cos = cos/sin = cot
2) sec(sec - cos) = 1/cos(1/cos - cos) = (1/cos2) - 1 = (1-cos2)/cos2 = sin2/cos2 = tan2
2006-09-05 22:53:40 · answer #5 · answered by linsay_william_harry 1 · 0⤊ 0⤋
clarify your question so people can give u better answers. :)
don't waste your 5 points. :)
2006-09-03 05:16:17 · answer #6 · answered by ←deadstar→ 3 · 0⤊ 0⤋