what is the solution set of the solutions a + 5b = 8 & 3a - 4b =14? ASAP. thank you!?

Answer 1

a + 5b = 8
so multiply by 3

3a + 15b = 24

subtract from the other equation

19b = 24 - 14 = 10

b = 10/19

substitute in equation b = 10/19
a +50/19 = 8

so, a = 112/19

Answer 2

Elimination of a

a + 5b = 8
3a - 4b = 14

-3(a) + (- 3)(5b) = -3(8)

Multiplying the top equation by - 3

-3a - 15b = -24
3a -4b = 14
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- 19b = -10
- 19b/-19 = -10/-19

Subtracting - 19 from both sides

b = 10/19

Insert the b value in to the top equation

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Solving for a

a + 5 (10/19) = 8

a + 50/19 = 8

Clear the fraction Multiply the equation by 19

19(a) + 19(50/19) = 19(8)

19a + 50 = 152
-50 -50

Subtracting - 50 from both sides

19a = 102

19a/19 = 102/19

a = 102/19

Insert the " a " value into the equation

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Top equation

a + 5b = 8

102/19 + 5(10/19) = 8

5.368421053 + 50/19 = 8

5.368421053 + 2.31578947 = 8

5.37 + 2.63 = 8

Rounded to two decimal places

8 = 8

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Bottom equation

3a - 4b = 14

3(102/19) - 4(10/19) = 14

306/19 - 40/19 = 14

16.10576316 - 2.105263158 = 14

Rounded up

16 - 2 = 14

14 = 14

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The answer is

a = 102/19

b = 10/19

Answer 3

Ok,
a+5b= 8-----(1)
3a-4b=14-----(2)

Now multiply eq (1) by 3 so that a will have a coefficient of 3,
now
from (1) * 3,
3a+15b=24-----(3)
now (3)-(2) gives,
19b=10 => b= 10/19

now substitute this b for eq (1), giving
a + 5.(10/19) = 8
then,
a = 8 - (50/19) = 102/19

Hope this helps!

Answer 4

multiply a+5b=8 by 4 and 3a-4b=14 by 5 and then add we will get a=102/19 then substitute a =102/19 in a+5b=8 we will get b=10/19

Answer 5

a + 5b = 8------(1)
3a - 4b =14----(2)

(2)=
3a - 4b= 14
a=14+4b/3 --------(3)

if we put the value in (1)

14+4b/3+5b=8
14 + 4b +15b/3 =8
14+19b=24
b=10/19

if we put this value in (3)

a= 14+4 x10/19/3
a= 266+40/19/3
a= 306/19/3

if we multiply=

306/19 x 1/3=102/19

so,

a= 102/19

b= 10/19

(solved) pretty easy...

Answer 6

a+5b=8
a=8-5b ...................(1)
3a-4b=14
-4b=14-3a multiplying by negative sign,we have
4b=3a-14
now substituting the value of a,we have
4b=3(8-5b)-14
4b=24-15b-14
4b=10-15b
4b+15b=10
19b=10
b=10/19.
now ,place this value in equation (1)
a=8-5b
a=8-5(10/19)
a=8-50/19
a=152-50/19
a=102/19

Answer 7

Multiply the first by -3

You will get
-3a-15b=-24

Add this to the second equation
-19b=-10

or b=10/19


from the first equation let us find a

a=102/19

Answer 8

a+5b=8,therefore
3a+15b=24.
now subtract the other equation from this one
19b=10
b=10/19
a=102/19

Answer 9

easiest way
5b=8 or b= 8/5
3a - 4(8/5) = 14
3a=14+ 4(8/5) = 14+(32/5) = 70/5+32/5 =102/5 =51
3a=51 or a=51/3 = 17
a=17, b=1.6

Answer 10

{-2,2}