2006-09-02 19:50:31 · 10 answers · asked by alim k 1 in Science & Mathematics ➔ Mathematics
depends on where parentheses are : (99^19)-(19^99) = -3.95 *10^126. 99^(19-19)^99 = 1 as anything raised to the 0 power is1. 99^(19-19^99) = is invalid, as you are trying to raise 19 to the -3.95*10^126 power.
2006-09-03 02:43:56 · answer #1 · answered by Matt H 1 · 0⤊ 0⤋
99^19 - 19^99=
-3.9500854841185254970240520975296 * 10^126
(the 99^19 is too small a number compared to the huge number 19^99 so therefore the actual question is "-19^99=")
2006-09-03 03:01:33 · answer #2 · answered by supersonic 2 · 0⤊ 0⤋
1
ne thing to da power 0 is 1
99^(19-19) = 1
1 ^ 99 = 1
so the answer is one
2006-09-03 09:20:06 · answer #3 · answered by Nikhil 2 · 0⤊ 0⤋
99^(19-19)(99) = 99^(0)(99) = 99^(0) = 1
one
2006-09-03 02:58:25 · answer #4 · answered by Will 2 · 0⤊ 0⤋
to the zero power or = 1
2006-09-06 23:05:57 · answer #5 · answered by answerer 2 · 0⤊ 0⤋
0
I think if 19-19 is in parathesis
2006-09-03 02:55:13 · answer #6 · answered by Ilooklikemyavatar..exactly 3 · 0⤊ 0⤋
d answer should be 0
2006-09-03 03:05:34 · answer #7 · answered by juhi 3 · 0⤊ 0⤋
zero (0)
2006-09-03 02:56:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋
0(zero)
2006-09-06 07:28:46 · answer #9 · answered by sonali 3 · 0⤊ 0⤋
-1.9 * 10^100
2006-09-03 02:53:56 · answer #10 · answered by Anonymous · 0⤊ 0⤋