which one of the following integers can be expressed as the sum of 100 consecutive integers?

Question

which one of the following integers can be expressed as the sum of 100 consecutive integers?

Answer 1

You have not mentioned any number.
sO I shall give an algebraic ans
let lowest number be
n
largest is n+99

so average = (2n+99)/2
sum = (2n+99)/2*100 = 50(2n+99)

any number of above form and lowest of the set of numbers is n

Answer 2

sum of the first consecutive 100 numbers:

sum=100/2(2*a+(100-1)*1))=50(2*a+99)=100*a+4950

where a is the first term of the series

so your condition would be to subtract 4950 from the given integer and see if it is a multiple of 100

Answer 3

Any integer in the set beginning with 5050 and indexed by 100. The general expression for the nth sum of m consecutive numbers is:

N=m*(m+2n-1)/2

Curiously (to me) the function generates sets of series beginning with the mth triangular and indexed by m.

Answer 4

what r the integers???

Answer 5

Do your own homework.