a set of five positive integers exists whose average,or mean,is 5;whose median is 5;and whose only mode is 8.what is the difference between the largest and smallest integers in the set?
2006-09-02 18:35:27 · 5 answers · asked by nakz 1 in Science & Mathematics ➔ Mathematics
1,3,5,8,8
The difference is 7.
2006-09-02 18:43:58 · answer #1 · answered by Anonymous · 0⤊ 1⤋
so, one of the 5 numbers is 5.
since the mean of 5 numbers is 5, sum of the 5 numbers must be = 5 x 5 = 25
Since, one of the numbers is 5, sum of other 4 numbers = 25 - 5 = 20
Now, the only Mode is 8, so 8 occurs at least twice. This means that, out of remaining 4 numbers, 8 comes at least 2 times.
Now because all numbers must be positive, 8 can not occur more than two times because 8x3 = 24!
So, u have 5,8,8 as 3 numbers. The rest two must ad up to = 20 - 8 - 8 = 4
Since, 8 was the only mode, we can not have the number two twice. So, the only other option is 1,3
Thus, ur numbers are 1,3,5,8,8
The diff between, largest and the smallest number is 8-1 = 7
2006-09-02 22:16:10 · answer #2 · answered by DG 3 · 0⤊ 0⤋
erm is it 12 and 7
2006-09-02 18:44:17 · answer #3 · answered by Dee 4 · 0⤊ 0⤋
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2016-11-24 19:23:50 · answer #4 · answered by ? 4 · 0⤊ 0⤋
I passed math. Your turn.
2006-09-02 18:40:28 · answer #5 · answered by AzOasis8 6 · 0⤊ 0⤋