If e^6x = 8
then x =
2006-09-02 11:58:27 · 6 answers · asked by Olivia 4 in Science & Mathematics ➔ Physics
Three rules you need:
ln (e^a) = a * ln (e)
ln (e) = 1
[ln (a)] / b = ln (a^(1/b))
e^6x = 8
ln (e^6x) = ln (8)
6x * ln (e) = ln (8)
6x = ln (8)
x = ln (8) / 6
x = ln (8^(1/6))
2006-09-02 13:08:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x = 1 2/3
2006-09-02 12:07:27 · answer #2 · answered by matthewsfx2 1 · 0⤊ 0⤋
x=0.34657359
Take the natural log of both sides.
Then 6x = ln(8) = 2.07944
x = 2.07944 / 6 = 0.34657359
2006-09-02 12:05:44 · answer #3 · answered by sandiego_roleplay 1 · 0⤊ 0⤋
you want to get x by itself, so to get rid of e, you take the natural log (ln) of both sides, and using the principles of logs you can move the exponent in front of the natural log giving you 6x = ln8. then you divide by 6 on both sides and you'll get x = (ln 8)/6
2006-09-02 12:03:52 · answer #4 · answered by saxon_148 2 · 0⤊ 0⤋
Well, 6x=ln8=2.07944. Divide this by 6 and you get x= 0.34657359.
2006-09-02 12:33:00 · answer #5 · answered by zee_prime 6 · 0⤊ 0⤋
Take log to the base e of each side.......
6x = ln8
so x = (ln8)/6
or x = ln8^(-6)
2006-09-02 12:06:44 · answer #6 · answered by Stewart H 4 · 0⤊ 0⤋