The fixed points of the function f(x) = 8x^2 are x = 0 and x = ?

0 ⤊

Did you get any of these answers?

... 1, only

... -1 and +1

... 4 only

... -4 and +4

... 1/4

... 1/2

or none of these

2006-09-02 11:45:04 · 2 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

x = 8 x^2
8 x^2 - x = 0
x (8x -1) = 0

So x = 0 or x= 1/8

Ana

2006-09-02 15:19:21 · answer #1 · answered by MathTutor 6 · 0⤊ 0⤋

Why ask this question again?

2006-09-02 12:47:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋