The slope of the secant line which passes thru the points where x = 1 and x = 3 on the curve y = x^2 ...is 4 ?

Question

Is 4 right?

Answer 1

f(x) = y = x^2
f(1) = 1
f(3) = 9

So the two points on the secant line are:
(1 , 1)
(3 , 9)

Slope = (y2 - y1) / (x2 - x1)
=(9 - 1) / (3 - 1)
=4

Answer 2

The slope of the quickly line passing with the aid of factors (0,-3) and (2,3) is calculated with the help of (3+3)/2=6/2=3 The slope of the tangent line to ln(x^3) on the element (a million,0) might nicely be discovered with the help of... a million. the by-made from ln(x^3)=3x^2/x^3 2. plug in x=a million to get 3/a million=3 So particular, 3=3 and the slopes are the comparable

Answer 3

Hmmm..

Secant line or is the line that crosses y=x^2 at (1,1) and (3, 9)?

if so then the slope m is
m=delta y/delta x=(9-1)/(3-1)=
m=8/2=4
So you are correct
Congratulations!

Answer 4

yes