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2006-09-02 10:27:14 · 5 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
yes.
2ln|x| = lnx^2=ln|x^2|, since x^2>0 for any x.
sweetie just gave the most wrong answer in the world...
2006-09-02 10:35:08 · answer #1 · answered by cybrdng 2 · 0⤊ 0⤋
Yes. The only possible issue that could arise is if x is negative. Suppose x = -3. Then we are considering whether ln(9) = 2 ln(3), which of course it does.
2006-09-02 17:32:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
To proof a statement is true you must use properties, not particular numbers.
ln|x^2| = ln|x||x|= ln|x| + ln|x| = 2ln|x| ... so the functions are the same only written in different forms.
2006-09-02 18:38:24 · answer #3 · answered by vahucel 6 · 0⤊ 0⤋
Absolutely
2006-09-02 19:25:38 · answer #4 · answered by Scott S 4 · 0⤊ 0⤋
Yes Thats True.
if y = ln |x^2|
x= 0
if y =2 ln |x|
x=0
same result.
but am ganna show you plot.
just click on the links ;
http://www.largeimagehost.com/image/upload-image/free-image-host/2012/mp1.PNG.html
http://www.largeimagehost.com/image/upload-image/free-image-host/2012/Mp2.PNG.html
good luck.
2006-09-02 17:38:13 · answer #5 · answered by sweetie 5 · 1⤊ 0⤋