What is the volume of a spherical shell of inner radius R and outer radius C? What is its surface area?

Answer 1

The volume of the sphere with radius C is (4pi/3)C^3.
The volume of the sphere with radius R is (4pi/3)R^3.
The volume of the shell =
(4pi/3)C^3 - (4pi/3)R^3 = (4pi/3)(C^3 - R^3).

The outer area = 4pi C^2
The inner area = 4pi R^2.
Th

Answer 2

Think about it this way. You're really dealing with two spheres.

For volume, calculate the larger volume, and subtract the smaller volume. This is the volume of the shell.
Recall that volume is 4/3 x pi x r-cubed.

So [4/3 x pi x C-cubed] - [4/3 x pi x R-cubed] = volume of shell.

For surface area, add the two surface areas together:
Recall that surface area is 4 x pi x r-squared

You get (4 x pi x C-squared) + (4 x pi x R-squared) = total surface area.

Good luck with the rest of the assignment! :-)

Answer 3

Find the volume of the entire object, pretending there is no hole in the middle:

V1 = (4/3)*pi*C^3

Find the volume of the inner hole:

V2 = (4/3)*pi*R^3

Find the difference:

V1 - V2 = (4/3)*pi*C^3 - (4/3)*pi*R^3 = (4pi/3)(C^3 - R^3)


To find the surface, you might include the outer surface and the inner surface

S1 = 4*pi*C^2

S2 = 4*pi*R^2

S1 + S2 = 4pi(C^2 + R^2)

Answer 4

volume= 4/3 times pi times (C raised to the third power-R raised to the third power)
surface area= 4 times pi times C squared.