The 2 in the part -10y2 is -10y squared.
2006-09-02 08:06:45 · 5 answers · asked by Thick Chick 2 in Science & Mathematics ➔ Mathematics
-10(y^2-36)=0
y=+/-6
2006-09-02 08:08:49 · answer #1 · answered by raj 7 · 1⤊ 0⤋
Sove the equation first.
-10 y^2 +360=0
-10 y^2 = -360
y^2 = -360 / -10
y ^2 = 36
y = + and - the square root of 36
y = +6 and -6
Factoring
-10y^2 +360=0
Use your solutions from above and set up in factored form
-10 (y+___) (y-___)
-10 (y+6) (y-6)
Above is your factored form.
Now check your work via foil method (first, outter, inner, last):
-10 (y+6) (y-6)
-10 (y^2 - 6y +6y -36) Now simplify
-10 (y^2 - 36) Now distribute -10
-10 y^2 + 360
This is the origional equation so you know that you have factored the problem correct.
Always check your work, and read your problem carefully to determine if it only wants you to factor the equation or if it wants you to solve the equation, or both.
Hope this helps and good luck!!!!
2006-09-06 07:30:53 · answer #2 · answered by exxavier 2 · 0⤊ 0⤋
-10y^2 + 360 = 0
Divide both sides by -10
y^2 - 36 = 0
This is the difference of perfect squares to factor
(y - 6)(y + 6) = 0
Set each factor equal to zero and you get your answer.
Hope this helps.
2006-09-02 08:13:12 · answer #3 · answered by SmileyGirl 4 · 2⤊ 0⤋
-10y^2+360=0
Minus 360 from both sides
-10y^2=-360
then divide by -10 on both sides
y^2=36
Then square root the number 36
Answer is y=6
2006-09-02 08:12:50 · answer #4 · answered by snooppoopaloop69 3 · 0⤊ 2⤋
-10y^2 + 360
-10(y^2 - 36)
-10(y - 6)(y + 6)
2006-09-02 08:36:28 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋