Regarding this problem 54-6x^2=0, look in details box.?

Question

There is no common factor, so how would I set this problem up?

Answer 1

54 - 6x^2 = 0

1) Add 6x^2 to both sides.

6x^2 = 54

2) Divide both sides by 6.

x^2 = 9

3) Take the square root of both sides.

x = 3

Answer 2

Actually you do have a common factor. Both 6 and 54 are divisible by 6. If you have to solve by factoring follow the steps below.

54 - 6x^2 = 0
Divide by 6

9 - x^2 = 0
Factor by the difference of perfect squares.

(3 - x)(3 + x) = 0
Set each factor equal to zero and solve for x.

You will get two answers, because you have an x^2 term.

Hope this helps.

Answer 3

54-6x^2=0
minus 54 from both sides
-6x^2=-54
then divide by negative 6 on both sides
x^2=9
then square root both sides
x=3
then u get 3

generally for problems like these, you just simplify until you isolate the x and its power, then its easily solvable

Answer 4

54 - 6x^2 = 0
-6x^2 + 54
-6(x^2 - 9)
-6(x - 3)(x + 3)

Answer 5

54 - 6x^2 = 0

-6x^2 = -54

Divide both sides by -6.

x^2 = 9

x = 3

Answer 6

This problem can be solved in 3 easy steps:

1.) subtract 54 from both sides of the equation.

2.) divide both sides by -6

3.) take the square root of both sides

answer will be both positive and negative (+/-) because any number squared can be positive or negative and have the same positive answer.

Answer 7

54-6x^2=0
-6x^2=-54
x^2=9
x=3

generally for problems like these, you just simplify until you isolate the x and its power, then its easily solvable

Answer 8

Well u got some answers but they are all incomplete!!

When x^2 = 9

x is either +3 or -3

So, u have 2 possible solutions for x

Answer 9

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Answer 10

-6(x^2-9)=0
x^2-9=0
(x+3)(x-3)=0
x+3=0 x=-3
x-3=0 x=3
so x= +/-3