Finding molarity of a diluted concentration?

Question

A standard solution is prepared for the analysis of fluoxymesterone (C20H29FO3), an anabolic steroid. A stock solution is first prepared by dissolving 10.0 mg of fluoxymesterone in enough water to give a total volume of 500.0 mL. A 100.0 microliter aliquot (portion) of this solution is diluted to a final volume of 100.0 mL. Calculate the concentration of the final solution in terms of molarity.

Answer 1

The concentration of your stock solution is

C0=mole/V0
and since mole=mass/MW you have C0=mass/(MW*V0)

For dilution you have C1V1=C2V2 =>
C2=(V1/V2)*C1
but C1=C0, so

C2=(V1/V2)*C0=>
C2= (V1/V2)* mass/(MW*V0)=>

C2=(V1*mass)/(V2*MW*V0)

You need to substitute with the values expressed in the appropriate way

So mass=10 mg= 10* 10^-3 g
V0= 500 ml= 0.5 L
V1= 100 microliter =100 *10^-6 L
V2= 100 ml = 100 * 10^-3 L
and MW=336 g/mole

C2= (100 *(10^-6) *10*(10^-3)) / (100*(10^-3) *336 *0.5)
C2=5.95 *10^-8 M

Answer 2

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