2006-09-02 06:37:18 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
suppose you want to convert 50*C to Fahrenheit
F=(9/5)*50+32=90+32=122*
(9/5)c+32=F
(9/5)c=f-32
c=(f-32)(5/9)
2006-09-02 06:39:34 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Your equation is actually the relationship between Fahrenheit and Celsius measurements of temperature...
Regardless, begin by getting rid of "32" by subtracting it from both sides:
f-32 = 9/5c
When you have a fraction being multiplied with the variable you want to solve for, you get rid of it by multiplying by its inverse: in this case, 5/9:
5/9 (f-32) = c
There's your answer. You can keep the left side of the equation factored like it is. Just remember to multiply the WHOLE side of the equation by the fraction.
Hope this helps!
2006-09-02 06:41:35 · answer #2 · answered by kookoonuts 2 · 0⤊ 0⤋
the equation you are refering to is the relationship between degrees farenheit(f) and degrees centigrade(c)
solving for c is straightforward algebra
f=9/5c+32
f-32=9/5c
5/9 * (f-32) = c
voila
good luck with algebra
2006-09-02 06:41:06 · answer #3 · answered by enginerd 6 · 0⤊ 0⤋
f=9/5c+32
f-32=9/5c
5/9(f-32)=c
soooo
5/9(f-32)=c
2006-09-02 06:39:38 · answer #4 · answered by taylorswift<3 3 · 0⤊ 0⤋
take 32 to the other side and multiply by 9/5...pretty much what JENNYCHEN said!!! Man, Asian smart girls are AWESOME!!!
2006-09-02 06:40:22 · answer #5 · answered by cbg_mx 3 · 0⤊ 0⤋
Ah yes.
The old Centigrade to Fahrenheit question.
2006-09-02 06:41:53 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Call your math teacher
2006-09-02 06:38:59 · answer #7 · answered by Anonymous · 1⤊ 0⤋