mathematics calculus 3 Vectors
2006-09-02 05:23:10 · 5 answers · asked by jrosales9@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics
Calculate the 3 lines in parameterized form as
x1 = x0 +ta
y1 = y0 +tb
z1 = z0 + tb
to get {a, b, c} a vector parallel to the given line. (Make life easy on yourself and assume t =1) Do this for both lines.
Now, if one vector is a scalar multiple of the other, the lines are parallel.
In this case, the answer is no, they aren't parallel.
Doug
2006-09-02 05:41:11 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
In order for two vectors to be parallel, both vectors must be scalar multiples of each other. Therefore, by definition, the vector (-4,6,1) & (-2,0,3) will not be parallel to (10,18,4) & (5,3,14).
2006-09-02 12:58:52 · answer #2 · answered by Andre R 1 · 0⤊ 0⤋
No, they are not parallel.
A direction vector for the first line is <-2,6,4>.
A direction vector for the second is <5,15,-10>.
Since one is not a scalar multiple of the other
the lines aren't parallel.
2006-09-02 12:50:29 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
Easy! The regulator system is directly respondent to the archival pattern path, this is also influenced by what's known as the "ventricular storage crossover" which can re-assign some trail decedent factors. I hope this answers your question...pretty obvious really
2006-09-02 12:24:36 · answer #4 · answered by Opera 3 · 0⤊ 0⤋
Yes, I believe it is.
2006-09-02 12:28:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋