Brooke,
-x/2 + 1/3x is an expression. You cannot solve expressions in algebra. Only equations or inequalities can be solved, which means "to find the value of the variable(s) that make the equation(s) or inequalities(s) true."
Expressions have directions like "simplify", "multiply", "factor" to name a few. I assume that you are to add the two fractions in your problem. Is that second fraction 1 divided by 3x or 1 divided by 3 and then multiply by x. I am guessing that it really is 1/(3x). If so, then you have to find the lowest common denominator just like you did in arithmetic. In your case the LCD is 6x. So,
-x/2 + 1/(3x)
= -3x^2/(6x) + 2/(6x) = (-3x^2 +2)/(6x)
2006-09-02 05:10:34
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answer #1
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answered by LARRY R 4
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the simplest method depends upon the other side of this equation. if it is zero, just take the L.C.M and then forget about he denominator. the numerator thus has -3x(pow 2) + 2=0 that makes it x(pow 2)=2/3. so x=square root of 2/3. if it is an inequality, 0 should be excluded as it makes the term infinity(denominator becomes zero). if the other side of equation has a non zero number, a quadratic expression is obtained which can be solved to find the value of x.
2006-09-02 02:03:54
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answer #2
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answered by Anonymous
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Can't solve something without an = sign in it somewhere, however it can be simplified:
-1/2 x + 1/3 x
-3/6 x + 2/6 x
-1/6 x
2006-09-02 01:50:25
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answer #3
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answered by anonymous_dave 4
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u have to make the denominators the same.
-x/2 + 1/3x the common denominator would be 6x
-3x^2/6x + 2/6x
(-3x^2 + 2)/6x
hmmm.. if the question is -x/2 + (1/3)x it's totally different:
-1/2 (x) + (1/3) x
-3x/6 + 2x/6 = -x/6
2006-09-02 03:43:49
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answer #4
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answered by sasmallworld 6
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1/2x + 1/3x
Change fractions to give same denominator: -3/6x + 2/6x
Take out factor of 1/6 (if you find that helps): 1/6(-3x + 2x)
Add: 1/6(-x)
Multiply: -1/6x
2006-09-06 00:01:36
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answer #5
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answered by Helen B 5
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I nearly got a pen and a bit of paper.. then thought nah - its Saturday.
2006-09-02 01:49:32
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answer #6
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answered by Smiler 5
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"Resolver problemas" additionally the occasion would be: "Me gustan las matemáticas porque soy bueno en RESOLVER PROBLEMAS" or you may say "Me gustan las matemáticas porque soy bueno RESOLVIENDO PROBLEMAS" the two are superb, yet for this reason, i think of the 1st is extra superb than the 2d.
2016-12-18 03:33:49
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answer #7
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answered by ? 4
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solve your problem by yourself
2006-09-02 01:47:26
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answer #8
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answered by The rocket 4
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you're inschool to LEARN this, see your parents or teacher for help.
2006-09-05 16:15:34
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answer #9
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answered by babysweetvee 3
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i don't like the look of that x
2006-09-02 01:56:30
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answer #10
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answered by Anonymous
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