When I have to convert .2rec, to a/b form I can divide 2 by 9, so its 2/9. Its true for .3rec, .4rec... up to .8. But how to convert .9recurring into a/b form. can anybody help?
2006-09-02 00:49:53 · 9 answers · asked by arnab 2 in Science & Mathematics ➔ Mathematics
9/9 0.9 recurring is the same as 1 as the number of 9's tend to infinite. On your pocket calculator (if it is old) 1/9 * 9 gives 0.99999 on the more modern ones it equals 1
2006-09-02 01:02:53 · answer #1 · answered by Chris C 2 · 2⤊ 0⤋
7
2006-09-02 00:56:35 · answer #2 · answered by Anonymous · 0⤊ 1⤋
let x=0.999999999....
multiply both sides by 10
10x=9.9999999999....
then subtract the first equation from second equation
therefore 9x=9
x=9/9=1
IT IS NOT EQUAL TO 1 BUT TENDS TO 1
2006-09-02 02:35:23 · answer #3 · answered by the1 1 · 0⤊ 1⤋
yeah, i too get ur point, since 9/9 would mean 1 which is surely not equal to .9 recurring. anyways, i dont think there is a solution to this problem. if there is, i will be sure to check it out here
2006-09-02 01:00:32 · answer #4 · answered by Artika 2 · 0⤊ 1⤋
It does not exist. It is always equal to 1.
2006-09-02 01:00:10 · answer #5 · answered by ars32 3 · 0⤊ 0⤋
i think the answer given by Chris C is correct
2006-09-02 03:30:31 · answer #6 · answered by Abhinav K 1 · 0⤊ 0⤋
i think 10 / 11
2006-09-02 01:23:00 · answer #7 · answered by ninad j 1 · 0⤊ 1⤋
i assume you are talking about fractions, if that is the case, 0.9999.... (infinity) is 3/3 or 1 whole...
2006-09-02 08:55:29 · answer #8 · answered by mcdonaldcj 6 · 0⤊ 0⤋
it cannot be
2006-09-02 01:31:41 · answer #9 · answered by Ravitej 2 · 0⤊ 0⤋