2006-09-02 00:43:51 · 10 answers · asked by Barca Fan 2 in Sports ➔ Football ➔ German Football
NO not a chance...
it's pretty obvious why.
2006-09-02 00:55:47 · answer #1 · answered by Arron never walk's alone 4 · 0⤊ 1⤋
I think they would have great chances to win La Liga even without one of these players. It's more difficult without both of them but they can win, anyway. Now if you talk about Champions League, they're chances to win would be much, much lower, cause you can replace Ronie & Eto'o but they have to find players to replace the replacmentes as well and it will be difficult then
2006-09-04 03:49:19 · answer #2 · answered by milanist_girl 4 · 0⤊ 0⤋
Have you seen Barca without Dinho? Eto´o is good, but Barca can´t do without Dinho, Eto´o was good in a bad team as Mallorca.
2006-09-02 17:27:20 · answer #3 · answered by Juan V 2 · 0⤊ 0⤋
would be a tough season if that ever happened, but they'd still have Saviola, Messi and Deco.
I can see them winning anyhow.
Messi and Saviola would be top scorers and Deco great at midfield...not to mention Puyol and Marquez as defenders.
They'd make it somehow! lol
2006-09-02 20:44:44 · answer #4 · answered by Barça! 4 · 0⤊ 0⤋
They would be some where on top ,but if they were replaced with some other good players they would win La Liga for sure !!!!!!
2006-09-02 13:51:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I think Messi & Ronaldinho make an excellent pair. I think the team would suffer an agonizing blow.
VAMOS BARCELONA!
2006-09-03 13:40:07 · answer #6 · answered by Sarah R :] 3 · 0⤊ 0⤋
They can but their chances of winning will be much lower..Eto'o will be missed for his goals and Ronaldinho for his technique..
2006-09-02 08:25:02 · answer #7 · answered by [V] 3 · 0⤊ 0⤋
they can. deco and messi can replace them.
2006-09-02 08:02:02 · answer #8 · answered by rizwano 7 · 1⤊ 0⤋
maybe,maybe not,who knows?!
2006-09-02 12:52:08 · answer #9 · answered by denise p 4 · 0⤊ 0⤋
no! because they cant replace him
2006-09-02 21:10:49 · answer #10 · answered by EL President 4 · 0⤊ 0⤋