4( 3 - 3x )( 8 - 2x^2 ) = 0?

Answer 1

4( 3 - 3x )( 8 - 2x^2 ) = 0

Divide both sides by 4 to get rid of it:
= ( 3 - 3x )( 8 - 2x^2 ) = 0

Factor out a 3 from the first and a 2 from the second:
= 3 ( 1 - x ) * 2 ( 4 - x^2 ) = 0
= 6 ( 1 - x ) ( 4 - x^2 ) = 0

Again divide both sides by 6 to get rid of that:
= ( 1 - x ) ( 4 - x^2 ) = 0

This is true if (1 - x ) = 0 or ( 4 - x^2 ) = 0

First equation:
1 - x = 0
x = 1

Second equation:
4 - x^2 = 0
4 = x^2
x = sqrt(4)
x = +/-2

So your answers are:
x = 1, x = 2 or x = -2

Answer 2

4(3-3x)(8-2x^2) =0
Dividing on both sides by 4(3-3x),
=> 4(3-3x)(8-2x^2)/4(3-3x)=0/4(3-3x),
=>8-2x^2=0
=> 2(4-x^2)=0
=>2(4- x^2)/2=0/2
=> 4-x^2 = 0
=> x^2 =4
=>x = square root of 4
=> x = +2 or - 2

Answer 3

x=0

Answer 4

x = 1, 2 and -2

Answer 5

4(3-3x)(8-2x^2)=0

get the greatest common factor of 8 and -2x^2.

the gcf is 2

after getting the gcf, factor out 2 from (8-2x^2).

the result will be 2(4-x^2).

our new equation will be 4(3-3x)(2)(4-x^2)=0.

multiply 4 and 2 in the left side of the equation and get
8(3-3x)(2)(4-x^2)=0.

you can still factor (4-x^2) to (2-x)(2+x) forming a new equation,
8(3-3x)(2-x)(2+x)=0.

divide 8 to both sides and get (3-3x)(2-x)(2+x)=0

there will be 3 solutions to this problem which are 3-3x=0, 2-x=0 and 2+x=0.

solution:
3-3x=0 (add -3 to both sides of the equation)
-3x=-3 (divide -3 to both sides of the equation)
x=1

or

2-x=0 (add -2 to both sides of the equation)
-x=-2 (multiply -1 to both sides of the equation)
x=2

or

2+x=0 (add -2 to both sides of the equation)
x=-2

so, the solutions for x are 1,2 and -2.
(x=1 or x=2 or x=-2)

Answer 6

devide by 4
(3-3x)(8-2x^2) = 0
3-3x = 0 or (8-2x^2) = 0

3- 3x =0 => x =1
8-2x^2= 0 =>x^2=4 so x = +/-2

so solution -2 or 1 or 2

Answer 7

4*3(1-x)*2(4-x^2)=0
then 24(1-x)(4-x^2)=0
dividing by 24 => (1-x)(4-x^2) =0
(1-x)[(2-x)(2+x)]=0
then 1-x= 0 ==> x=1
or 2-x= 0 ==> x=2
or 2+x=0 ==> x=-2

Answer 8

In just 3 conditions : x=1 and x=2 and x=-2

Answer 9

Assuming you mean 2x^2 + 3x - 3 = 0... Quadratic formulation is (-b +/- sqrt(b^2 - 4*a*c))/2a. that's disgusting in textual content textile format, yet bypass with me. Substituting in a, b, and c... (-3 +/- sqrt(3^2 - 4*2*(-3)))/(2*2) = (-3 +/- sqrt(33))/4 = (-3 + sqrt(33)) / 4 and (-3 - sqrt(33)) / 4. Assuming my head-math is real, there is your answer. i'm going to bypass away simplification as much as you.

Answer 10

What is the point of the 4?

Either set of brackets has to equal 0.

So X=1 (to make 1st set of brackets 0) or
X=2 or -2 (to make 2nd set of brackets 0)