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A car traveling at a speed of vo = 57 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 110 m.

a) What is its acceleration during the time it is stopping?
b) How long (what amount of time) does it take for the car to come to a stop?
c) After the car has gone 1/3 of the stopping distance, what is its speed?

2006-09-01 19:26:57 · 1 answers · asked by hardik p 1 in Science & Mathematics Physics

1 answers

For these types of problems, you generally need to use three equations:
S = (V1^2 - V2^2)/2a
Vf = Vo + a * t
S = Vo * t + 1/2 a * t * t.

From the first equation, you can determine acceleration (a) from the known distance (S) and the initial and final velocities. Once you have acceleration, you can use the second equation to determine time (t) and once you have both of those, you can recalculate the new speed and times for the third problem.

2006-09-01 19:50:37 · answer #1 · answered by Kurt 3 · 2 0

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