Find an equation for a line which passes thru the point (1, -2) and which is perpendicular to the line given by x + y - 4 = 0 .
2006-09-01 11:13:37 · 7 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
x + y - 4 = 0
y = -x + 4; slope of line = -1
The slope of a line perpendicular to this one = 1
So what is the y-intercept of the line in question? Substitute:
(-2) = (1)(1) + b
-2 = 1 + b
-3 = b
The equation of the line is y = x - 3
2006-09-01 11:28:02 · answer #1 · answered by jimbob 6 · 2⤊ 0⤋
thats not too hard. Here, lets look at it this way the coefficients for a line are as follows for that form ax+by+c=0 and slope is defined as -a/b so.
-1/1 is the slope of the line given and since the 2 lines are perpendicular, that means that you will take the negative reciprical (switch the numerator and the denominator, then take the negative of that) which in this case=1.
So, with the new given information, and the points you have for the other line you can put that in the point-slope form
(y-ysub1)=m(x-xsub1)+b
y+2=1(x-1)+0
y=x-3
thus, the equation for your line is y=x-3
2006-09-01 19:38:24 · answer #2 · answered by Tom 2 · 0⤊ 0⤋
y=x-2
2006-09-01 18:18:03 · answer #3 · answered by NONAME 2 · 0⤊ 1⤋
Can anyone figure that out? Yeah, you can if you pay attention in class and use your brain!!
2006-09-01 18:19:22 · answer #4 · answered by ? 3 · 0⤊ 2⤋
y=-x-2 i think
2006-09-01 18:15:49 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Friday is not the day for question like sure...;-)
2006-09-01 18:16:34 · answer #6 · answered by Island Girl 5 · 0⤊ 1⤋
hm...
hm..
y=x-2
or more
2006-09-01 18:21:03 · answer #7 · answered by julean33 2 · 0⤊ 1⤋