How do you turn 2(16/X-3)=5X into a quadratic equation?

0 ⤊

How do you turn 2(16/X-3)=5X into a quadratic equation?

Show work

2006-09-01 10:52:42 · 3 answers · asked by Katey 1 in Education & Reference ➔ Homework Help

3 answers

1) x not equal with 0
2) 2(16/x-3) =5x
2(16-3x)/x = 5x
32 -6x = 5x^2
5X^2 + 6x -32 =0 ( it's not true for x = 0)

2006-09-01 11:05:30 · answer #1 · answered by aiaia57 3 · 0⤊ 0⤋

Notice how you have an "x" in the denominator on the left hand side? So multiply both sides of the equation by "x" to get rid of it. That gives you 2(16 - 3x) = 5x^2, or 5x^2 +6x -32 = 0

2006-09-01 17:58:50 · answer #2 · answered by Larry 6 · 0⤊ 0⤋

multiply both sides by x:
32-6x=5x^2
5x^2+6x-32=0

2006-09-01 17:59:40 · answer #3 · answered by odu83 7 · 0⤊ 0⤋