2006-09-01 10:36:54 · 6 answers · asked by Doug 2 in Science & Mathematics ➔ Mathematics
e^x+y - e^2x+y = 0
x = 2y / e^2 - product log [-e ^ ((2y/e2)-2) ]
x = 0.27 y 1 . product log [ -1.2.7182 ^ 0,27]
Good luck
2006-09-01 10:49:24 · answer #1 · answered by sweetie 5 · 1⤊ 2⤋
2*y + e^x *(1-e^x)
2006-09-01 17:42:58 · answer #2 · answered by nima_iran_1985 3 · 1⤊ 0⤋
You need to put some parentheses in your expression to make it clear what you mean.
Do you mean:
exp(x+y) - exp(2x+y)
or
exp(x) + y - exp(2x) + y
or
exp(x) + y - exp(2)*x + y
or perhaps even something else?
2006-09-01 17:46:56 · answer #3 · answered by hfshaw 7 · 0⤊ 0⤋
You need to put some parentheses in to clarify whether the "+y" s are in the exponents or not.
2006-09-01 17:48:17 · answer #4 · answered by zandyandi 4 · 2⤊ 0⤋
considering you meant e^(x + y) - e^(2x + y) =
(e^x - 1)(-e^(x+y))
2006-09-01 17:45:02 · answer #5 · answered by Pedromdrp 2 · 0⤊ 0⤋
2y+e^x-e²x? I'm not sure you can simplify it any more than that.
2006-09-01 17:42:08 · answer #6 · answered by Pascal 7 · 0⤊ 0⤋