no the answer is (x+5)/(x+4)
2006-09-01 10:25:50
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answer #1
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answered by bretttwarwick 3
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You should get:
(x+5)/(x+4)
[(x+6)(x+2) / (x+6)(x-2)] / [(x+4)(x+2) / (x+5)(x-2)]
Of course, the solution is valid for:
x NOT equal to -6, 2, -5, -4, -2 as any of these values would zero out your denominators.
2006-09-01 10:41:44
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answer #2
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answered by Shivers 2
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Don't plug it into your calculator, factor the quadratic expressions and cancel like terms!
Your expression factors as:
(x+6)(x+2)/((x+6)(x-2))
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(x+4)(x+2)/((x+5)(x-2))
= (x+5)/(x+4)
2006-09-01 10:42:29
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answer #3
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answered by hfshaw 7
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I get 1/[(x-2)^2(x+4)(x+5)]
2006-09-01 10:29:27
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answer #4
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answered by Thermo 6
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My calculator yelled at me about not using variables so no I did not get that.
2006-09-01 10:35:33
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answer #5
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answered by TheDude 3
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Ask this to prof Steven Hawking, he is very good at mathematics.
2006-09-01 10:28:17
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answer #6
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answered by Waky 2
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no :-s
11,520
2006-09-01 10:33:28
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answer #7
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answered by Anonymous
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