are there anybody that want speak with me on yahoo?
sorry for my english...!!!
2006-09-01 10:04:10 · 10 answers · asked by ♥little angel♥ 6 in Family & Relationships ➔ Friends
i am 14... if there are anybody... contact me at stefy927@yahoo.it....
2006-09-02 04:08:53 · update #1
Bonjurno.
Always wanted to learn Italian. Don't apologize for your English either. It's better than most English-speaking people.
Ciao
2006-09-01 10:06:52 · answer #1 · answered by Quasimodo 7 · 2⤊ 0⤋
A decade ago to learn English, you had to attend costly English classes or purchase course material like tapes and books. Now you can learn English for free from the comfort of your home using the internet. The BBC and the British Council offer a number of online courses which teach written and spoken English. You can also improve your English by watching television programs and reading English newspapers. For more information, visit http://tinyurl.com/qnzpt
2006-09-03 19:57:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Sono spiacente ma non capisco Engish
2006-09-01 10:06:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I`ll do it. always wanted to speak to an Italian person.
2006-09-01 10:10:05 · answer #4 · answered by dnlrawson 4 · 0⤊ 0⤋
sure! why not? i've always wanted to know many people from all over the world! my source is down below. e-mail me if you want : ) don't apologize for your english, cause many people have problems w/ that, including me!! : )
2006-09-01 10:16:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋
You want to chat with someone English? Sure, if you want to chat then message me...
2006-09-01 10:06:23 · answer #6 · answered by Gavin T 7 · 0⤊ 0⤋
sorry i dont have yahoo messenger but u can email me at caithorvath@yahoo.com
2006-09-01 10:25:03 · answer #7 · answered by caitlyn h 2 · 0⤊ 0⤋
Sure.
bawinmmfs@yahoo.com
2006-09-01 10:13:59 · answer #8 · answered by bawinmmfs 1 · 0⤊ 0⤋
of course i will
2006-09-01 10:06:17 · answer #9 · answered by cocopuff4o4 1 · 0⤊ 0⤋
sure
2006-09-01 10:05:48 · answer #10 · answered by soapdad_1968 2 · 0⤊ 0⤋