If x > 0, then In x + In (x+1) + In (x+2) =?

Answer 1

ln(x) + ln(x + 1) + ln(x + 2)

ln(x(x + 1)(x + 2))

ln(x(x^2 + x + 2x + 2))

ln(x(x^2 + 3x + 2))

ln(x^3 + 3x^2 + 2x)

Answer 2

In x + In (x+1) + In (x+2) =
ln{x(x+1)(x+2)}

Answer 3

I'm assuming that what they're looking for is a simplification of this expression into one logarithm.

Remember that log A + log B = log AB.

So this becomes ln [ x(x+1)(x+2) ]

which is ln (x³ + 3x² + 2x)

Hope that helps!

Answer 4

ln (a) + ln (b) = ln (a*b)

So the answer is

ln (x*(x+1)*(x+2))