exactly four different points
exactly three different points
exactly two different points.
exactly one point.
or
The graphs don't intersect at all.
What do you think?
2006-09-01 09:46:23 · 9 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
never intersect at three differnt points because of x^2
maximum is only two points or one point
in this case do not intersect at all!!!!!
because b^2 - 4ac < 0
2006-09-01 10:06:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2
2006-09-01 09:52:09 · answer #2 · answered by petestokalovich 2 · 0⤊ 0⤋
2
2006-09-01 09:51:23 · answer #3 · answered by bretttwarwick 3 · 0⤊ 0⤋
No intersection.
y = x^2 – 6x + 6 is a parabola with minimum at ( 3, -3 )
2x + 3y + 9 = 0 is a line with slope -2 / 3 which passes through (0, -3) and (3, -5 ), so there is no intersection.
2006-09-01 15:05:19 · answer #4 · answered by h2 2 · 0⤊ 0⤋
y = x^2 - 6x + 6 and
2x + 3y + 9 = 0
y = x^2 - 6x + 6 and
y = -(2/3)x - 3
At the intersection x^2 - 6x + 6 = -(2/3)x - 3
x^2 -(6 - 2/3)x + 9 = 0
The discriminator is <0, so no solutions, so no intersecting points.
2006-09-01 11:02:25 · answer #5 · answered by Thermo 6 · 0⤊ 0⤋
Ugh. Plug the first equation into the second equation. Solve for x.
2x + 3(x^2-6x+6) + 9=0
Find x, plug it in the 1st (or second, for all I care), find y. PROFIT.
2006-09-01 09:52:20 · answer #6 · answered by rahidz2003 6 · 0⤊ 0⤋
y=x^2-6x+6
2x+3y+9=0
y=x^2-6x+6
y= -(2/9)x-1/3
x^2 -6x+(2/9)x+6+1/3 =0
y = -(2/9)x -1/3
A. x^2-(6-2/9)x +19/3 =0
x^2 -52/9x+19/3=0
Δ = (52/9)^2-4(19/3) = 8.0....>0
Exactly two different points
2006-09-01 10:04:53 · answer #7 · answered by eaismeg 3 · 0⤊ 0⤋
I think somebody needs to get busy and remember how to solve simultaneous equations ☺
(Hint: The first two are *definitely* out ☺)
Doug
2006-09-01 09:49:32 · answer #8 · answered by doug_donaghue 7 · 0⤊ 0⤋
it should be exact.
0 = is the end point.
= so it's sharp - or EXACT
2006-09-01 09:54:01 · answer #9 · answered by ♫♫♫ EL Dindo 3 · 0⤊ 0⤋