If (x - 1)/(x + 3) > (x + 1)/(x - 3) , then ....?

Question

x < -3 or 0 < x < 3 ?



-3 < x < 0 or 3 < x ?

Answer 1

(x - 1)/ (x +3) > (x+1)/(x-3)

(x-1) *((x-3) > (x+1) * (x+3)

-8x >0

x < 0 (a)
x < -3 or o from a and b this answer is x < -3

Answer 2

3 < x

Answer 3

The answer to x=1

(1-1)/(1+3) > (1+1)/(1-3) =
0/4= 0 > 2/-2 = -1

Therefore, -3< x <0

Answer 4

Well J Russell ;
(x - 1)/(x + 3) > (x + 1)/(x - 3)
we need to get the main form of (x - 1)/(x + 3) & (x + 1)/(x - 3) ,
step 1;
▪ if f(x1) = (x - 1)/(x + 3) = (x*x) + (x*3) + (1-*x) + (-1*3) =
x^2 + 3x -x - 3 = x^2 +2x -3

▪ if f(x2) = ((x + 1)/(x - 3) = (x*x) + (x*-3) + (1*x) + (1*-3) =
x^2 - 3x +x - 3 = x^2 -2x -3

Step 2;
now put them back
f(x1) > f(x2)
so we have ;
x^2 +2x -3 > x^2 -2x -3
[ x^2 - x^2 ] + [2x +2x ] > -3 +3
0 + 4x > 0
4x > 0
x> 0/4
x>0

Answer 5

once you combine a polynomial, you purely try this to each and each term: Ax^n --> (A/(n+a million))x^(n+a million) you purely enhance the exponent by ability of one, then divide the coefficient by ability of the recent exponent. So to your subject we've: (a million/4)x^4 + a million/(2x^2) + (a million/2)x^2 observe the 2nd term became in basic terms x^(-3) so as that makes it -(a million/2)x^(-2).

Answer 6

-3 < x < 0

If 3 < x then the equations don't work!

Answer 7

Homework?

Answer 8

x>0 isn't it?

Answer 9

ask a mathmetician i cannot be arsed to work it out lol

Answer 10

then its 3....i mean 1.....i dont no man....wut is that....is that math??????hahhhahahhhahhahahhaah....thats funny...