the sum of two numbers is 16. the larger number is one more than twice the smaller number. What is the smaller number?
could it be 11 i dont know i dont get this
2006-09-01 08:16:49 · 11 answers · asked by islAnd_paradisex4 1 in Science & Mathematics ➔ Mathematics
If X = the smaller # and Y= the larger #, then
X+Y=16 and 2X+1=Y
The next step would be:
X +2X+1=16
3X + 1 = 16
3X=15
so, X =5, 2X+1 = 11
So, the answer to the problem would be 5, because they are asking the value of the smaller number.
2006-09-01 08:25:49 · answer #1 · answered by helpful mom 2 · 0⤊ 0⤋
Ok
There are a lot of it on yahoo every time with different numbers so i will give you the general receipt
the sum of two numbers is 16
I write : x + y = 16
The larger number is one more than twice the smaller number
say that x is the largernumber, y the smaller number
I write : x = 2*y + 1
There is no more information
Now I solve the system of lineair equations :
(A) x + y = 16
(B) x = 2*y + 1
2*y + 1 + y = 16 => 3y = 15 => y = 5, and from (A) i get x +5 = 16 => x = 11.
CAPITO ?
2006-09-01 08:23:35 · answer #2 · answered by gjmb1960 7 · 0⤊ 0⤋
Call the larger number x, the other number y.
x + y = 16
x = 1 + 2 y
Substitute the bottom equation in the top equation:
(1 + 2y) + y = 16
1 + 3y = 16
3y = 15
y = 5
x = 16 - 5 = 11
2006-09-01 08:22:53 · answer #3 · answered by dutch_prof 4 · 1⤊ 0⤋
With any word problem, you just need to find a way to represent the words with an equation, using letters to represent the values you don't know yet.
So, your two numbers are x and y, and the words of the problem specify two relationships.
sum of two number is 16
x + y = 16
larger is onr more than twice smaller, say x is the smaller.
y = 2x + 1
Then use whatever technique you're learning in class to solve the two equations for x and y
2006-09-01 09:14:17 · answer #4 · answered by Ken H 4 · 0⤊ 0⤋
L + S = 16
L = 2S+1
2S+1+ S = 16
3S +1 = 16
3S = 15
S = 5
2006-09-01 08:24:24 · answer #5 · answered by Roy G. Biv 3 · 0⤊ 0⤋
the only thing that could be is 11 because
11/2=5
& 5 +11=16.
2006-09-01 09:43:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
This is two equations.
x+y=16
x-1=2y
x is the larger number, y the smaller. Solve for x in the first equation, then substitute it into the second. Solve that for y.
2006-09-01 08:19:45 · answer #7 · answered by Cadair360 3 · 0⤊ 0⤋
ya 11 is the big, 5 is the small...11 is one more than twice size of 5
2006-09-01 08:19:42 · answer #8 · answered by kirupahost 2 · 1⤊ 0⤋
A+B= 16
A= 1+ 2B
A+1+2B=16
3A+1=16
3A= 16-1
A=15/3
A=5
A+B=16
5+B=16
B=16-5
B=11
2006-09-01 08:29:09 · answer #9 · answered by Anonymous · 0⤊ 0⤋
5 and 11
U have
x + y = 16
y = 2x +1
solution, x=5, y=11
2006-09-01 08:21:27 · answer #10 · answered by monarca_08 1 · 1⤊ 0⤋