and A is equal to B and B = B miles per gallon@ 1,333,34 lbs What is the value of B ? Or in other words since I probably didn't state that right. If an 18wheeler gets 6 MPG weighing 80,000lbs what would a compact car weighing 1,333.34lbs get for MPG if it were pound for pound equal to the truck?
2006-09-01 07:22:12 · 6 answers · asked by Love is the principle thing 4 in Science & Mathematics ➔ Mathematics
Basic Algebra, 359.998 mpg.
2006-09-01 07:39:37 · answer #1 · answered by crazypranks 2 · 0⤊ 0⤋
Assuming that the engines of both vehicles are equal then you determine the ratio of the first:
6/80000 ~ X/1333.34. Solve for X. To solve this take the 6 divide by 80k then multiply by the weight of the car.
Think through the question. It is a ratio of one to the other. If you think of it this way then the answer is easy to understand.
If you have to decide between getting the answer and understanding how it is derived then go with the understanding. This is the same philosophy as giving someone a fish vs. teaching them to fish.
Learn.
2006-09-01 07:32:53 · answer #2 · answered by NW_iq_140 2 · 0⤊ 0⤋
Assuming the entire energy of the fuel is converted to motion or Kinetic energy
KE of truck = KE of Car
or 80000 * 6*6 = 1333.34 *v*v
So, v = 46.48 MPG
2006-09-01 07:43:18 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋
359.9982 MPG
2006-09-01 07:31:21 · answer #4 · answered by monarca_08 1 · 0⤊ 0⤋
take 80,000 divided by 1333.34 and multiply by 6
You're on your own from there
2006-09-01 07:30:55 · answer #5 · answered by xox_bass_player_xox 6 · 0⤊ 0⤋
Answer it yourself
2006-09-01 07:23:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋