What is the equation of the line that passes through (5,−3), (8,2)?

Answer 1

You should be doing your own homework

Answer 2

First, you find the slope. That's "rise over run," or the change in y divided by the change in x. Here, y goes from 5 to 8 and x from -3 to 2, so that's 3/5 or 0.6. Now, you need to apply that slope to find the y-intercept, the y value when x = 0. Starting with the x value of 5 at the first point, we need to change x by -5. That means that y changes by -5 * slope = -5 * 3/5 = -3. y at the first point was -3, so it goes to -6. Now, with the slope and the y-intercept, we can express this line in slope-intercept form. y = slope*x + intercept, or y = -(3/5)x - 6.

Answer 3

y = 5/3 x - 34/3

to get the slope: change in y/ change in x:
(2-(-3) )/ (8-5) = 5/3

Then plug the slope, which we refer to as "m" into this equation: y=mx +b
y = 5/3 x + b
Then plug in one set of coordinates into the equation to find out what "b" is:
We will use the first set of coordinates:

-3 = (5/3)* (5) + b
-3 = 25/3 + b
-3 - 25/3 = b
-9/3 - 25/3 = b
-34/3 = b

So, y = 5/3x -34/3 is the answer.

Answer 4

y=mx+c
------------

step 1:
m=(2--3)/(8-5)


step 2:
say, at point (8,2)
2=m(8)+c

then after calculating c, you'll get ur equation.
work on your homework,you can do it=)

Answer 5

slope formula: m= y2-y1 over x2-x1


(5, -3) (8, 2)
x1 y1 x2 y2

so:

m= 2-(-3) over 8-5
= 5 over 3 rise/run

Answer 6

the equation is (y-y1)/(y2-y1)=(x-x1)/(x2-x1)
substituting (y+3)/(2+3)=(x-5)/(8-5)
cross multiplying 3(y+3)=5(x-5)
=>3y+9=5x-25
transposing 5x-3y-34=0

Answer 7

y = (5/3)x - (34/3)

You should learn it's so easy !!!

and do ur own homework !!!!!!!!1

DAVID made a mistake calculating b

so this is the good one !!