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Please answer ASAP!!!!!

2006-09-01 06:39:01 · 6 answers · asked by S. Sharma 1 in Science & Mathematics Chemistry

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2006-09-01 06:48:02 · update #1

6 answers

It appears to be the anion of sarcosine.

I'm guessing that the molecule is incorrectly depicted; it should have one more hydrogen (attached to one of the red O atoms), and then it actually would be sarcosine (aka N-methylglycine).

2006-09-01 07:25:00 · answer #1 · answered by Mr. E 5 · 1 0

you sure it has only 1 O. normally O is in blue which would make the molecule an ether of sorts. just go over iupac rules and you can do your own homework

2006-09-01 07:18:14 · answer #2 · answered by shiara_blade 6 · 0 1

Try L-Serine beta-lactone with the amino group protonated, such as L-Serine beta-lactone tetraflouroborate without the BF4- ion.
Aldrich, 2005-2006 p. 2088

NH3+
|
/ \
\ /=O
O

2006-09-01 07:13:20 · answer #3 · answered by Anonymous · 0 1

Mr. E and I agree -- this is the conjugate base form of sarcosine, or N-methyl glycine.

H3C-NH-CH2-C(O)O-

2006-09-01 07:35:22 · answer #4 · answered by Dave_Stark 7 · 0 0

that would be the elusive "h6c3o2n" molecule.

-eagle

2006-09-01 06:48:06 · answer #5 · answered by eaglemyrick 4 · 1 2

unsaturated.

There are many possible configurations.

2006-09-01 06:42:29 · answer #6 · answered by Tesla 2 · 0 2

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